What is the answer to ln(4)-ln(3)=2ln(x)-ln(x+1) ?

The answer to ln(4)-ln(3)=2ln(x)-ln(x+1) is x=2

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ln(4)-ln(3)=2ln(x)-ln(x+1)

ln (4) - ln (3) = 2 ln (x) - ln (x + 1)

x = 2

Solution steps

ln (4) - ln (3) = 2 ln (x) - ln (x + 1)

Add

ln (3)

to both sides

ln (4) - ln (3) + ln (3) = 2 ln (x) - ln (x + 1) + ln (3)

Simplify

ln (4) = 2 ln (x) - ln (x + 1) + ln (3)

Apply log rules

4 (x + 1) = x^{2} \cdot 3

Solve

4 (x + 1) = x^{2} \cdot 3 : x = 2, x = - \frac{2}{3}

x = 2, x = - \frac{2}{3}

Verify Solutions:

x = 2

True

, x = - \frac{2}{3}

False

The solution is

x = 2

lo g_{2 - x} (2 x^{2} - 5 x + 2) = 2

4 = - lo g_{10} (x)

lo g_{8} (4 x + 4) = 2

x, y^{2} + ln (x + y^{2}) = x + 3

12 x^{2} ln (x) + 7 x^{2} = 0

What is the answer to ln(4)-ln(3)=2ln(x)-ln(x+1) ?
The answer to ln(4)-ln(3)=2ln(x)-ln(x+1) is x=2
Solve for x: ln(4)-ln(3)=2ln(x)-ln(x+1)
The solution is x=2