What is the answer to solvefor x,y^2+ln(x+y^2)=x+3 ?

The answer to solvefor x,y^2+ln(x+y^2)=x+3 is x=-\W(-1/(e^{2y^2-3)})-y^2

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solvefor x,y^2+ln(x+y^2)=x+3

solve for

x, y^{2} + ln (x + y^{2}) = x + 3

x = - W (- \frac{1}{e ^{2 y^{2} - 3}}) - y^{2}

Solution steps

y^{2} + ln (x + y^{2}) = x + 3

Move

y^{2}

to the right side

ln (x + y^{2}) = x + 3 - y^{2}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x + y^{2})} = e^{x + 3 - y^{2}}

Simplify

e^{l n (x + y^{2})} : x + y^{2}

x + y^{2} = e^{x + 3 - y^{2}}

Solve

x + y^{2} = e^{x + 3 - y^{2}} : x = - W (- \frac{1}{e ^{2 y^{2} - 3}}) - y^{2}

x = - W (- \frac{1}{e ^{2 y^{2} - 3}}) - y^{2}

Verify Solutions:

x = - W (- \frac{1}{e ^{2 y^{2} - 3}}) - y^{2}

True

The solution is

x = - W (- \frac{1}{e ^{2 y^{2} - 3}}) - y^{2}

12 x^{2} ln (x) + 7 x^{2} = 0

lo g_{10} (3 x + 1) = 2

lo g_{10} (x) 5 = lo g_{10} (5 x)

2 lo g_{5} (6 x + 5) = 6

5 + 2 ln (x) = 8

What is the answer to solvefor x,y^2+ln(x+y^2)=x+3 ?
The answer to solvefor x,y^2+ln(x+y^2)=x+3 is x=-\W(-1/(e^{2y^2-3)})-y^2