What is the answer to log_{2}(x^2+2x-4)=2 ?

The answer to log_{2}(x^2+2x-4)=2 is x=2,x=-4

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log_{2}(x^2+2x-4)=2

lo g_{2} (x^{2} + 2 x - 4) = 2

x = 2, x = - 4

Solution steps

lo g_{2} (x^{2} + 2 x - 4) = 2

Apply log rules

x^{2} + 2 x - 4 = 4

Solve

x^{2} + 2 x - 4 = 4 : x = 2, x = - 4

x = 2, x = - 4

lo g_{8} (5 - x) = 2

lo g_{x} (x^{2} - 1) = 2

y, lo g_{y} (137) = x

lo g_{2} (2 x + 16) = 2

3 ln^{2} (x) + ln (x) = 2

What is the answer to log_{2}(x^2+2x-4)=2 ?
The answer to log_{2}(x^2+2x-4)=2 is x=2,x=-4
Solve for x: log_{2}(x^2+2x-4)=2
The solution is x=2,x=-4