What is the answer to log_{2}(10+3x)=5 ?

The answer to log_{2}(10+3x)=5 is x= 22/3

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log_{2}(10+3x)=5

lo g_{2} (10 + 3 x) = 5

x = \frac{22}{3}

Decimal

x = 7.33333 \dots

Solution steps

lo g_{2} (10 + 3 x) = 5

Apply log rules

10 + 3 x = 32

Solve

10 + 3 x = 32 : x = \frac{22}{3}

x = \frac{22}{3}

lo g_{2} (1 + x) = 6

y, ln (y) = x

lo g_{3} (x^{2} + 2) = 3

lo g_{10} (4 x) + lo g_{10} (2) = lo g_{10} (48)

lo g_{\frac{1}{4}} (9 - 5 x) = - 3

What is the answer to log_{2}(10+3x)=5 ?
The answer to log_{2}(10+3x)=5 is x= 22/3
Solve for x: log_{2}(10+3x)=5
The solution is x= 22/3