What is the answer to log_{10}(4x)+log_{10}(2)=log_{10}(48) ?

The answer to log_{10}(4x)+log_{10}(2)=log_{10}(48) is x=6

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log_{10}(4x)+log_{10}(2)=log_{10}(48)

lo g_{10} (4 x) + lo g_{10} (2) = lo g_{10} (48)

x = 6

Solution steps

lo g_{10} (4 x) + lo g_{10} (2) = lo g_{10} (48)

Move

lo g_{10} (2)

to the right side

lo g_{10} (4 x) = lo g_{10} (48) - lo g_{10} (2)

Apply log rules

4 x = 24

Solve

4 x = 24 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

lo g_{\frac{1}{4}} (9 - 5 x) = - 3

lo g_{2} (3 x - 1) = 9

x, y = - lo g_{10} (x)

ln (3 x + 6) - ln (12 x) = 0

lo g_{2} (x) + lo g_{2} (4) = lo g_{2} (16)

What is the answer to log_{10}(4x)+log_{10}(2)=log_{10}(48) ?
The answer to log_{10}(4x)+log_{10}(2)=log_{10}(48) is x=6
Solve for x: log_{10}(4x)+log_{10}(2)=log_{10}(48)
The solution is x=6