What is the answer to solvefor y,log_{y}(1/x)=-2 ?

The answer to solvefor y,log_{y}(1/x)=-2 is y=e^{(ln(x))/2} {0 1}

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solvefor y,log_{y}(1/x)=-2

solve for

y, lo g_{y} (\frac{1}{x}) = - 2

y = e^{\frac{l n ( x )}{2}} {0 < x < 1 or x > 1}

Solution steps

lo g_{y} (\frac{1}{x}) = - 2

Apply log rules

\frac{ln ( \frac{1}{x} )}{ln ( y )} = - 2

Multiply both sides by

ln (y)

\frac{ln ( \frac{1}{x} )}{ln ( y )} ln (y) = - 2 ln (y)

Apply log rules

y = e^{\frac{l n ( x )}{2}}

Verify Solutions:

y = e^{\frac{l n ( x )}{2}} {0 < x < 1 or x > 1}

The solution is

y = e^{\frac{l n ( x )}{2}} {0 < x < 1 or x > 1}

lo g_{2} (x^{2} + 4 x + 3) = 3

lo g_{2 x} (3 x^{2} + 9 x - 14) = 2

2 + 3 ln (x) = 7

2 lo g_{10} (x) = lo g_{10} (x) + 3

lo g_{x} (2) = - \frac{1}{2}

What is the answer to solvefor y,log_{y}(1/x)=-2 ?
The answer to solvefor y,log_{y}(1/x)=-2 is y=e^{(ln(x))/2} {0<x<1\lor x>1}