What is the answer to log_{2}(3x+4)=5 ?

The answer to log_{2}(3x+4)=5 is x= 28/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(3x+4)=5

lo g_{2} (3 x + 4) = 5

x = \frac{28}{3}

Decimal

x = 9.33333 \dots

Solution steps

lo g_{2} (3 x + 4) = 5

Apply log rules

3 x + 4 = 32

Solve

3 x + 4 = 32 : x = \frac{28}{3}

x = \frac{28}{3}

lo g_{10} (5 x^{2} - 21 x) = \frac{2}{5}

2 lo g_{10} (x) - lo g_{10} (x + 6) = 0

10 lo g_{5} (9 x - 5) = 35

2 lo g_{10} (x) = 3 + lo g_{10} (\frac{x}{10})

60 = 10 lo g_{10} (x)

What is the answer to log_{2}(3x+4)=5 ?
The answer to log_{2}(3x+4)=5 is x= 28/3
Solve for x: log_{2}(3x+4)=5
The solution is x= 28/3