What is the answer to log_{1/5}(2x-3)=-2 ?

The answer to log_{1/5}(2x-3)=-2 is x=14

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log_{1/5}(2x-3)=-2

lo g_{\frac{1}{5}} (2 x - 3) = - 2

x = 14

Solution steps

lo g_{\frac{1}{5}} (2 x - 3) = - 2

Apply log rules

2 x - 3 = 25

Solve

2 x - 3 = 25 : x = 14

x = 14

lo g_{10} (2 x + 8) = 2

lo g_{10} (8 x) - lo g_{10} (2) = lo g_{10} (32)

x, z = \frac{ln ( x - 7 )}{y}

lo g_{10} (x) + lo g_{10} (x + 48) = 2

3 lo g_{2} (x + 2) = 15

What is the answer to log_{1/5}(2x-3)=-2 ?
The answer to log_{1/5}(2x-3)=-2 is x=14
Solve for x: log_{1/5}(2x-3)=-2
The solution is x=14