What is the answer to solvefor x,z=(ln(x-7))/y ?

The answer to solvefor x,z=(ln(x-7))/y is x=e^{zy}+7

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solvefor x,z=(ln(x-7))/y

solve for

x, z = \frac{ln ( x - 7 )}{y}

x = e^{zy} + 7

Solution steps

z = \frac{ln ( x - 7 )}{y}

Switch sides

\frac{ln ( x - 7 )}{y} = z

Multiply both sides by

y

ln (x - 7) = zy

Apply log rules

x - 7 = e^{zy}

Solve

x - 7 = e^{zy} : x = e^{zy} + 7

x = e^{zy} + 7

lo g_{10} (x) + lo g_{10} (x + 48) = 2

3 lo g_{2} (x + 2) = 15

lo g_{x} (3) = 4

8 - ln^{3} (x) = 0

lo g_{\frac{1}{4}} (x) = - 2

What is the answer to solvefor x,z=(ln(x-7))/y ?
The answer to solvefor x,z=(ln(x-7))/y is x=e^{zy}+7