What is the answer to 8-ln^3(x)=0 ?

The answer to 8-ln^3(x)=0 is x=e^2

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8-ln^3(x)=0

8 - ln^{3} (x) = 0

x = e^{2}

Decimal

x = 7.38905 \dots

Solution steps

8 - ln^{3} (x) = 0

Rewrite the equation with

ln (x) = u

8 - u^{3} = 0

Solve

8 - u^{3} = 0 : u = 38

u = 38

Substitute back

u = ln (x),

solve for

x

Solve

ln (x) = 38 : x = e^{2}

x = e^{2}

Verify Solutions:

x = e^{2}

True

The solution is

x = e^{2}

lo g_{\frac{1}{4}} (x) = - 2

3 ln (3 x - 4) - 5 = 9

lo g_{3} (x^{2} - 5 x - 23) = 0

x, lo g_{8} (x - 6) = 60

lo g_{10} ((x - 2)^{2}) = 12