What is the answer to solvefor x,log_{2}(3x+5)=z ?

The answer to solvefor x,log_{2}(3x+5)=z is x=(2^z-5)/3

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solvefor x,log_{2}(3x+5)=z

solve for

x, lo g_{2} (3 x + 5) = z

x = \frac{2 ^{z} - 5}{3}

Solution steps

lo g_{2} (3 x + 5) = z

Apply log rules

3 x + 5 = 2^{z}

Solve

3 x + 5 = 2^{z} : x = \frac{2 ^{z} - 5}{3}

x = \frac{2 ^{z} - 5}{3}

\frac{2}{3} lo g_{10} (x) = 6

20 lo g_{10} (x) = 6

lo g_{x} (x^{2} - 1) = 2

x, ln (y) = ln (x) + c

lo g_{4} (x^{2} + 5 x + 6) = 1

What is the answer to solvefor x,log_{2}(3x+5)=z ?
The answer to solvefor x,log_{2}(3x+5)=z is x=(2^z-5)/3