What is the answer to log_{2}(2x-5)=5 ?

The answer to log_{2}(2x-5)=5 is x= 37/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(2x-5)=5

lo g_{2} (2 x - 5) = 5

x = \frac{37}{2}

Decimal

x = 18.5

Solution steps

lo g_{2} (2 x - 5) = 5

Apply log rules

2 x - 5 = 32

Solve

2 x - 5 = 32 : x = \frac{37}{2}

x = \frac{37}{2}

3 + lo g_{10} (2 x + 5) = 2

lo g_{a} (125) = 3

lo g_{3} (x + 3) = 4

0 = ln (x^{2} - 16)

lo g_{16} (x) = - \frac{3}{4}

What is the answer to log_{2}(2x-5)=5 ?
The answer to log_{2}(2x-5)=5 is x= 37/2
Solve for x: log_{2}(2x-5)=5
The solution is x= 37/2