What is the answer to log_{10}(x)+log_{10}(x+2)=8 ?

The answer to log_{10}(x)+log_{10}(x+2)=8 is x=(-2+sqrt(400000004))/2

Solve for x: log_{10}(x)+log_{10}(x+2)=8

The solution is x=(-2+sqrt(400000004))/2

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lo g_{10} (x) + lo g_{10} (x + 2) = 8

x = \frac{- 2 + 400000004}{2}

Decimal

x = 9999.00005

Solution steps

lo g_{10} (x) + lo g_{10} (x + 2) = 8

Apply log rules

x (x + 2) = 100000000

Solve

x (x + 2) = 100000000 : x = \frac{- 2 + 400000004}{2}, x = \frac{- 2 - 400000004}{2}

x = \frac{- 2 + 400000004}{2}, x = \frac{- 2 - 400000004}{2}

Verify Solutions:

x = \frac{- 2 + 400000004}{2}

True

, x = \frac{- 2 - 400000004}{2}

False

The solution is

x = \frac{- 2 + 400000004}{2}

lo g_{10} (x) + lo g_{10} (x + 2) = 2

x, t (x) = lo g_{4} (x + 2)

ln (x) = \frac{3}{2}

ln (x^{2}) = 0

lo g_{a} (8) = 6

What is the answer to log_{10}(x)+log_{10}(x+2)=8 ?
The answer to log_{10}(x)+log_{10}(x+2)=8 is x=(-2+sqrt(400000004))/2
Solve for x: log_{10}(x)+log_{10}(x+2)=8
The solution is x=(-2+sqrt(400000004))/2