What is the answer to log_{0.1}(x^2+3x)=-1 ?

The answer to log_{0.1}(x^2+3x)=-1 is x=2,x=-5

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log_{0.1}(x^2+3x)=-1

lo g_{0.1} (x^{2} + 3 x) = - 1

x = 2, x = - 5

Solution steps

lo g_{0.1} (x^{2} + 3 x) = - 1

Apply log rules

x^{2} + 3 x = 10

Solve

x^{2} + 3 x = 10 : x = 2, x = - 5

x = 2, x = - 5

3 x^{2} ln (x) + x^{2} = 0

lo g_{3} (x) + 1 = 0

lo g_{3} (2 x) - lo g_{3} (x + 5) = 0

2 ln (x) - ln (3) = 0

1 + lo g_{3} (x + 1) = 0

What is the answer to log_{0.1}(x^2+3x)=-1 ?
The answer to log_{0.1}(x^2+3x)=-1 is x=2,x=-5
Solve for x: log_{0.1}(x^2+3x)=-1
The solution is x=2,x=-5