What is the answer to solvefor y,sqrt(ln(2y))=x ?

The answer to solvefor y,sqrt(ln(2y))=x is y=(e^{x^2})/2 {x>= 0}

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solvefor y,sqrt(ln(2y))=x

solve for

y, ln (2 y) = x

y = \frac{e ^{x^{2}}}{2} {x \geq 0}

Solution steps

ln (2 y) = x

Rewrite the equation with

ln (2 y) = u

u = x

Solve

u = x : u = x^{2} {x \geq 0}

u = x^{2} {x \geq 0}

Substitute back

u = ln (2 y),

solve for

y

Solve

ln (2 y) = x^{2} : y = \frac{e ^{x^{2}}}{2}

y = \frac{e ^{x^{2}}}{2}

Verify Solutions:

y = \frac{e ^{x^{2}}}{2} {x \geq 0}

The solution is

y = \frac{e ^{x^{2}}}{2} {x \geq 0}

2 lo g_{2} (x - 4) + lo g_{2} (2) = 3

lo g_{10} (x^{2}) = - 2

ln (1 - x) = \frac{10}{3} x - 4.16

lo g_{2} (x - 3) = 0

lo g_{x} (2 x^{2} - 9 x + 14) = 2

What is the answer to solvefor y,sqrt(ln(2y))=x ?
The answer to solvefor y,sqrt(ln(2y))=x is y=(e^{x^2})/2 {x>= 0}