What is the answer to log_{3}(2x+1)-3=0 ?

The answer to log_{3}(2x+1)-3=0 is x=13

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log_{3}(2x+1)-3=0

lo g_{3} (2 x + 1) - 3 = 0

x = 13

Solution steps

lo g_{3} (2 x + 1) - 3 = 0

Move

3

to the right side

lo g_{3} (2 x + 1) = 3

Apply log rules

2 x + 1 = 27

Solve

2 x + 1 = 27 : x = 13

x = 13

Verify Solutions:

x = 13

True

The solution is

x = 13

\frac{1}{2} = ln (x)

lo g_{2} (5 x) = 15

ln (2 x - 7) + ln (4) = 3

lo g_{a} (16) = 2

5 x^{4} ln (x) + x^{4}

What is the answer to log_{3}(2x+1)-3=0 ?
The answer to log_{3}(2x+1)-3=0 is x=13
Solve for x: log_{3}(2x+1)-3=0
The solution is x=13