What is the answer to log_{10}(x^2)=-0.407 ?

The answer to log_{10}(x^2)=-0.407 is x= 1/(\sqrt[2000]{10^{407)}},x=-1/(\sqrt[2000]{10^{407)}}

Solve for x: log_{10}(x^2)=-0.407

The solution is x= 1/(\sqrt[2000]{10^{407)}},x=-1/(\sqrt[2000]{10^{407)}}

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lo g_{10} (x^{2}) = - 0.407

x = \frac{1}{2000 1 0 ^{407}}, x = - \frac{1}{2000 1 0 ^{407}}

Solution steps

lo g_{10} (x^{2}) = - 0.407

Apply log rules

x^{2} = \frac{1}{1 0 ^{0.407}}

Solve

x^{2} = \frac{1}{1 0 ^{0.407}} : x = \frac{1}{2000 1 0 ^{407}}, x = - \frac{1}{2000 1 0 ^{407}}

x = \frac{1}{2000 1 0 ^{407}}, x = - \frac{1}{2000 1 0 ^{407}}

15 = 19 ln (3 x + 3)

lo g_{x + 5} (2 x^{2} - 7 x + 7) = 2

lo g_{x} (\frac{4}{9}) = - 2

lo g_{10} (x) - lo g_{10} (x + 2) = 1

lo g_{10} (x + 6) = lo g_{10} (x) + lo g_{10} (6)

What is the answer to log_{10}(x^2)=-0.407 ?
The answer to log_{10}(x^2)=-0.407 is x= 1/(\sqrt[2000]{10^{407)}},x=-1/(\sqrt[2000]{10^{407)}}
Solve for x: log_{10}(x^2)=-0.407
The solution is x= 1/(\sqrt[2000]{10^{407)}},x=-1/(\sqrt[2000]{10^{407)}}