What is the answer to ln(x)-ln(x^2)= 1/2 ?

The answer to ln(x)-ln(x^2)= 1/2 is x= 1/(sqrt(e))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(x)-ln(x^2)= 1/2

ln (x) - ln (x^{2}) = \frac{1}{2}

x = \frac{1}{e}

Decimal

x = 0.60653 \dots

Solution steps

ln (x) - ln (x^{2}) = \frac{1}{2}

Apply log rules

x = \frac{1}{e}

Verify Solutions:

x = \frac{1}{e}

True

The solution is

x = \frac{1}{e}

lo g_{10} (2 x) + lo g_{10} (x) = lo g_{10} (5) + 1

ln (x) + ln (x + 1) = 4

lo g_{\frac{1}{6}} (3 - 10 x) = - 2

lo g_{10} (3 x + 1) - lo g_{10} (2 x - 3) = 1 - lo g_{10} (5)

5 x^{4} ln (x) + x^{4} = 0

What is the answer to ln(x)-ln(x^2)= 1/2 ?
The answer to ln(x)-ln(x^2)= 1/2 is x= 1/(sqrt(e))
Solve for x: ln(x)-ln(x^2)= 1/2
The solution is x= 1/(sqrt(e))