What is the answer to log_{10}(8x)-log_{10}(2)=log_{10}(16) ?

The answer to log_{10}(8x)-log_{10}(2)=log_{10}(16) is x=4

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log_{10}(8x)-log_{10}(2)=log_{10}(16)

lo g_{10} (8 x) - lo g_{10} (2) = lo g_{10} (16)

x = 4

Solution steps

lo g_{10} (8 x) - lo g_{10} (2) = lo g_{10} (16)

Move

lo g_{10} (2)

to the right side

lo g_{10} (8 x) = lo g_{10} (16) + lo g_{10} (2)

Apply log rules

8 x = 32

Solve

8 x = 32 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

8 x ln (x) + 4 x = 0

x, y^{2} = ln (x^{2} + y^{2})

lo g_{8} (5 - x) = lo g_{8} (6)

x, ln (x) = ln (y) + b + a y

ln (4 x - 7) = ln (x + 11)

What is the answer to log_{10}(8x)-log_{10}(2)=log_{10}(16) ?
The answer to log_{10}(8x)-log_{10}(2)=log_{10}(16) is x=4
Solve for x: log_{10}(8x)-log_{10}(2)=log_{10}(16)
The solution is x=4