What is the answer to solvefor x,y^2=ln(x^2+y^2) ?

The answer to solvefor x,y^2=ln(x^2+y^2) is x=sqrt(e^{y^2)-y^2},x=-sqrt(e^{y^2)-y^2}

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solvefor x,y^2=ln(x^2+y^2)

solve for

x, y^{2} = ln (x^{2} + y^{2})

x = e^{y^{2}} - y^{2}, x = - e^{y^{2}} - y^{2}

Solution steps

y^{2} = ln (x^{2} + y^{2})

Apply log rules

e^{y^{2}} = x^{2} + y^{2}

Solve

e^{y^{2}} = x^{2} + y^{2} : x = e^{y^{2}} - y^{2}, x = - e^{y^{2}} - y^{2}

x = e^{y^{2}} - y^{2}, x = - e^{y^{2}} - y^{2}

lo g_{8} (5 - x) = lo g_{8} (6)

x, ln (x) = ln (y) + b + a y

ln (4 x - 7) = ln (x + 11)

lo g_{10} (2 x - 2) = - 1

lo g_{x} (2) = 4

What is the answer to solvefor x,y^2=ln(x^2+y^2) ?
The answer to solvefor x,y^2=ln(x^2+y^2) is x=sqrt(e^{y^2)-y^2},x=-sqrt(e^{y^2)-y^2}