What is the answer to log_{10}((x-1)^2)=0 ?

The answer to log_{10}((x-1)^2)=0 is x=2,x=0

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log_{10}((x-1)^2)=0

lo g_{10} ((x - 1)^{2}) = 0

x = 2, x = 0

Solution steps

lo g_{10} ((x - 1)^{2}) = 0

Apply log rules

(x - 1)^{2} = 1

Solve

(x - 1)^{2} = 1 : x = 2, x = 0

x = 2, x = 0

lo g_{- 2 x - 4} (2 x^{2} - 14) = 2

x, 3.5 = 3.75 + lo g_{10} (x)

lo g_{\frac{1}{3}} (x) = \frac{1}{27}

(lo g_{10} (x))^{2} + 2 lo g_{10} (x) = 3

lo g_{10} (x) + lo g_{10} (x + 5) = 1

What is the answer to log_{10}((x-1)^2)=0 ?
The answer to log_{10}((x-1)^2)=0 is x=2,x=0
Solve for x: log_{10}((x-1)^2)=0
The solution is x=2,x=0