What is the answer to log_{2}(2^x+3)=2-x ?

The answer to log_{2}(2^x+3)=2-x is x=0

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log_{2}(2^x+3)=2-x

lo g_{2} (2^{x} + 3) = 2 - x

x = 0

Solution steps

lo g_{2} (2^{x} + 3) = 2 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (2^{x} + 3)} = 2^{2 - x}

Simplify

2^{l o g_{2} (2^{x} + 3)} : 2^{x} + 3

2^{x} + 3 = 2^{2 - x}

Solve

2^{x} + 3 = 2^{2 - x} : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

lo g_{1 + x} (\frac{400}{13}) = 20

2 \times lo g_{3} (x) - 23 = 17

2 lo g_{5} (x - 2) = 6

2 (4 x ln (x) + 2 x) = 0

lo g_{10} (8) + lo g_{10} (x) = 1

What is the answer to log_{2}(2^x+3)=2-x ?
The answer to log_{2}(2^x+3)=2-x is x=0
Solve for x: log_{2}(2^x+3)=2-x
The solution is x=0