What is the answer to 0.25=-0.25log_{e}(1-c) ?

The answer to 0.25=-0.25log_{e}(1-c) is c=(-1+e)/e

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0.25=-0.25log_{e}(1-c)

0.25 = - 0.25 lo g_{e} (1 - c)

c = \frac{- 1 + e}{e}

Decimal

c = 0.63212 \dots

Solution steps

0.25 = - 0.25 lo g_{e} (1 - c)

Switch sides

- 0.25 lo g_{e} (1 - c) = 0.25

Divide both sides by

- 0.25

lo g_{e} (1 - c) = - 1

Apply log rules

1 - c = \frac{1}{e}

Solve

1 - c = \frac{1}{e} : c = \frac{- 1 + e}{e}

c = \frac{- 1 + e}{e}

Verify Solutions:

c = \frac{- 1 + e}{e}

True

The solution is

c = \frac{- 1 + e}{e}

lo g_{4} (2 x - 5) = 4

26 = 10 lo g_{10} (\frac{I}{1 0 ^{- 16}})

lo g_{10} (x + 9) = lo g_{10} (x) + lo g_{10} (9)

lo g_{10} (2 x - 1) = 10

ln (3 x + 5) = 8

What is the answer to 0.25=-0.25log_{e}(1-c) ?
The answer to 0.25=-0.25log_{e}(1-c) is c=(-1+e)/e