What is the answer to x+log_{10}(x+9)=1 ?

The answer to x+log_{10}(x+9)=1 is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-9

Solve for x: x+log_{10}(x+9)=1

The solution is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-9

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x + lo g_{10} (x + 9) = 1

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 9

Decimal

x = 0.04365 \dots

Solution steps

x + lo g_{10} (x + 9) = 1

Move

x

to the right side

lo g_{10} (x + 9) = 1 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x + 9)} = 1 0^{1 - x}

Simplify

1 0^{l o g_{10} (x + 9)} : x + 9

x + 9 = 1 0^{1 - x}

Solve

x + 9 = 1 0^{1 - x} : x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 9

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 9

Verify Solutions:

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 9

True

The solution is

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 9

d, p = 42.6 + 26 lo g_{10} (d) + 20

lo g_{8} (x) = (\frac{4}{3})

\frac{- 2 ln ( x ) + 1}{x ^{3}} = 0

y, lo g_{y} (x) = 2

ln (x) + ln (x + 1) = 7

What is the answer to x+log_{10}(x+9)=1 ?
The answer to x+log_{10}(x+9)=1 is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-9
Solve for x: x+log_{10}(x+9)=1
The solution is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-9