What is the answer to ln(3x)+ln(6x)=2 ?

The answer to ln(3x)+ln(6x)=2 is x=e^{(2-ln(18))/2}

Solve for x: ln(3x)+ln(6x)=2

The solution is x=e^{(2-ln(18))/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (3 x) + ln (6 x) = 2

x = e^{\frac{2 - l n ( 18 )}{2}}

Decimal

x = 0.64070 \dots

Solution steps

ln (3 x) + ln (6 x) = 2

Apply log rules

x = e^{\frac{2 - l n ( 18 )}{2}}

Verify Solutions:

x = e^{\frac{2 - l n ( 18 )}{2}}

True

The solution is

x = e^{\frac{2 - l n ( 18 )}{2}}

0 = lo g_{3} (2 x - 3) - 4

ln (x) = \frac{1}{8}

x, lo g_{2} (x) = 5

2 lo g_{10} (x) = 10

x ln (x) = x

What is the answer to ln(3x)+ln(6x)=2 ?
The answer to ln(3x)+ln(6x)=2 is x=e^{(2-ln(18))/2}
Solve for x: ln(3x)+ln(6x)=2
The solution is x=e^{(2-ln(18))/2}