What is the answer to log_{7}(x^2+3x)=2 ?

The answer to log_{7}(x^2+3x)=2 is x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2

Solve for x: log_{7}(x^2+3x)=2

The solution is x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{7} (x^{2} + 3 x) = 2

x = \frac{- 3 + 205}{2}, x = \frac{- 3 - 205}{2}

Decimal

x = 5.65891 \dots, x = - 8.65891 \dots

Solution steps

lo g_{7} (x^{2} + 3 x) = 2

Apply log rules

x^{2} + 3 x = 49

Solve

x^{2} + 3 x = 49 : x = \frac{- 3 + 205}{2}, x = \frac{- 3 - 205}{2}

x = \frac{- 3 + 205}{2}, x = \frac{- 3 - 205}{2}

lo g_{x + 1} (x^{2} + 3) = 2

6 lo g_{x} (27) = 18

lo g_{10} (x) + lo g_{10} (x + 4) = 5

lo g_{10} (x) + lo g_{10} (x + 4) = 1

lo g_{x} (2) = 0.3562

What is the answer to log_{7}(x^2+3x)=2 ?
The answer to log_{7}(x^2+3x)=2 is x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2
Solve for x: log_{7}(x^2+3x)=2
The solution is x=(-3+sqrt(205))/2 ,x=(-3-sqrt(205))/2