What is the answer to log_{4}(x^2+15)=3 ?

The answer to log_{4}(x^2+15)=3 is x=7,x=-7

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log_{4}(x^2+15)=3

lo g_{4} (x^{2} + 15) = 3

x = 7, x = - 7

Solution steps

lo g_{4} (x^{2} + 15) = 3

Apply log rules

x^{2} + 15 = 64

Solve

x^{2} + 15 = 64 : x = 7, x = - 7

x = 7, x = - 7

\frac{- 3 ln ( x ) + 1}{x ^{4}} = 0

lo g_{3} (12 - 5 x) = 2

ln (3 x + 2) = ln (5 x - 6)

- lo g_{10} (k) = 3.14

a, lo g_{10} (a) = 3

What is the answer to log_{4}(x^2+15)=3 ?
The answer to log_{4}(x^2+15)=3 is x=7,x=-7
Solve for x: log_{4}(x^2+15)=3
The solution is x=7,x=-7