What is the answer to 17=10log_{10}((280)/x) ?

The answer to 17=10log_{10}((280)/x) is x=(14*2^{3/10})/(5^{7/10)}

Solve for x: 17=10log_{10}((280)/x)

The solution is x=(14*2^{3/10})/(5^{7/10)}

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17 = 10 lo g_{10} (\frac{280}{x})

x = \frac{14 \cdot 2 ^{\frac{3}{10}}}{5 ^{\frac{7}{10}}}

Decimal

x = 5.58673 \dots

Solution steps

17 = 10 lo g_{10} (\frac{280}{x})

Switch sides

10 lo g_{10} (\frac{280}{x}) = 17

Divide both sides by

10

lo g_{10} (\frac{280}{x}) = \frac{17}{10}

Apply log rules

\frac{280}{x} = 1 0^{\frac{17}{10}}

Multiply both sides by

x

\frac{280}{x} x = 1 0^{\frac{17}{10}} x

Simplify

1 0^{\frac{17}{10}} x : 1 0^{1 + \frac{7}{10}} x

280 = 1 0^{1 + \frac{7}{10}} x

Solve

280 = 1 0^{1 + \frac{7}{10}} x : x = \frac{14 \cdot 2 ^{\frac{3}{10}}}{5 ^{\frac{7}{10}}}

x = \frac{14 \cdot 2 ^{\frac{3}{10}}}{5 ^{\frac{7}{10}}}

Verify Solutions:

x = \frac{14 \cdot 2 ^{\frac{3}{10}}}{5 ^{\frac{7}{10}}}

True

The solution is

x = \frac{14 \cdot 2 ^{\frac{3}{10}}}{5 ^{\frac{7}{10}}}

lo g_{x + 6} (9) = 2

lo g_{2} (4) + lo g_{2} (c - 9) = 5

lo g_{3} (5 x - 4) = 4

lo g_{2 x - 5} (3 x^{2} - 5 x - 19) = 2

lo g_{2} (x^{3}) = 12

What is the answer to 17=10log_{10}((280)/x) ?
The answer to 17=10log_{10}((280)/x) is x=(14*2^{3/10})/(5^{7/10)}
Solve for x: 17=10log_{10}((280)/x)
The solution is x=(14*2^{3/10})/(5^{7/10)}