What is the answer to log_{2x-5}(3x^2-5x-19)=2 ?

The answer to log_{2x-5}(3x^2-5x-19)=2 is x=4,x=11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2x-5}(3x^2-5x-19)=2

lo g_{2 x - 5} (3 x^{2} - 5 x - 19) = 2

x = 4, x = 11

Solution steps

lo g_{2 x - 5} (3 x^{2} - 5 x - 19) = 2

Apply log rules

\frac{ln ( 3 x ^{2} - 5 x - 19 )}{ln ( 2 x - 5 )} = 2

Multiply both sides by

ln (2 x - 5)

\frac{ln ( 3 x ^{2} - 5 x - 19 )}{ln ( 2 x - 5 )} ln (2 x - 5) = 2 ln (2 x - 5)

Simplify

ln (3 x^{2} - 5 x - 19) = 2 ln (2 x - 5)

Apply log rules

3 x^{2} - 5 x - 19 = (2 x - 5)^{2}

Solve

3 x^{2} - 5 x - 19 = (2 x - 5)^{2} : x = 4, x = 11

x = 4, x = 11

Verify Solutions:

x = 4

True

, x = 11

True

The solutions are

x = 4, x = 11

lo g_{2} (x^{3}) = 12

6.3 = - ln (16 - a) + 7

lo g_{2} (7 - x) = 5

ln (9 x) + 1 = 0

lo g_{7} (x^{2} - 6 x) = 1

What is the answer to log_{2x-5}(3x^2-5x-19)=2 ?
The answer to log_{2x-5}(3x^2-5x-19)=2 is x=4,x=11
Solve for x: log_{2x-5}(3x^2-5x-19)=2
The solution is x=4,x=11