What is the answer to 6.3=-ln(16-a)+7 ?

The answer to 6.3=-ln(16-a)+7 is a=-e^{0.7}+16

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6.3=-ln(16-a)+7

6.3 = - ln (16 - a) + 7

a = - e^{0.7} + 16

Decimal

a = 13.98624 \dots

Solution steps

6.3 = - ln (16 - a) + 7

Move

ln (16 - a)

to the left side

6.3 + ln (16 - a) = 7

Move

6.3

to the right side

ln (16 - a) = 0.7

Apply log rules

16 - a = e^{0.7}

Solve

16 - a = e^{0.7} : a = - e^{0.7} + 16

a = - e^{0.7} + 16

Verify Solutions:

a = - e^{0.7} + 16

True

The solution is

a = - e^{0.7} + 16

lo g_{2} (7 - x) = 5

ln (9 x) + 1 = 0

lo g_{7} (x^{2} - 6 x) = 1

lo g_{5} (x + 1) = 3

lo g_{10} (3 x + 5) + lo g_{10} (x) = 1

What is the answer to 6.3=-ln(16-a)+7 ?
The answer to 6.3=-ln(16-a)+7 is a=-e^{0.7}+16
Solve for a: 6.3=-ln(16-a)+7
The solution is a=-e^{0.7}+16