What is the answer to log_{10}(5)+log_{10}(x+4)=2 ?

The answer to log_{10}(5)+log_{10}(x+4)=2 is x=16

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log_{10}(5)+log_{10}(x+4)=2

lo g_{10} (5) + lo g_{10} (x + 4) = 2

x = 16

Solution steps

lo g_{10} (5) + lo g_{10} (x + 4) = 2

Move

lo g_{10} (5)

to the right side

lo g_{10} (x + 4) = 2 - lo g_{10} (5)

Apply log rules

x + 4 = 20

Solve

x + 4 = 20 : x = 16

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

3 lo g_{10} (5 x) = - 9

y, lo g_{x - y} (8) = - 3

\frac{x}{2} = x ln (x^{2})

\frac{ln ( x ^{3} )}{4} = (ln (x))^{3}

3 - lo g_{2} (5 x - 2) = 0

What is the answer to log_{10}(5)+log_{10}(x+4)=2 ?
The answer to log_{10}(5)+log_{10}(x+4)=2 is x=16
Solve for x: log_{10}(5)+log_{10}(x+4)=2
The solution is x=16