What is the answer to log_{10}(x)+log_{10}(x+5)=2 ?

The answer to log_{10}(x)+log_{10}(x+5)=2 is x=(-5+5sqrt(17))/2

Solve for x: log_{10}(x)+log_{10}(x+5)=2

The solution is x=(-5+5sqrt(17))/2

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lo g_{10} (x) + lo g_{10} (x + 5) = 2

x = \frac{- 5 + 5 17}{2}

Decimal

x = 7.80776 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 5) = 2

Apply log rules

x (x + 5) = 100

Solve

x (x + 5) = 100 : x = \frac{- 5 + 5 17}{2}, x = \frac{- 5 - 5 17}{2}

x = \frac{- 5 + 5 17}{2}, x = \frac{- 5 - 5 17}{2}

Verify Solutions:

x = \frac{- 5 + 5 17}{2}

True

, x = \frac{- 5 - 5 17}{2}

False

The solution is

x = \frac{- 5 + 5 17}{2}

u, lo g_{u} (\frac{15}{16}) = v

lo g_{2} (6 \cdot 2^{2 n + 1} - 6) = n

lo g_{10} (x) - lo g_{10} (9) = 1

6.7 = lo g_{10} (\frac{I}{1})

lo g_{9} (x) = 5

What is the answer to log_{10}(x)+log_{10}(x+5)=2 ?
The answer to log_{10}(x)+log_{10}(x+5)=2 is x=(-5+5sqrt(17))/2
Solve for x: log_{10}(x)+log_{10}(x+5)=2
The solution is x=(-5+5sqrt(17))/2