What is the answer to log_{2}(x)+log_{4}(x)+log_{16}(x)=7 ?

The answer to log_{2}(x)+log_{4}(x)+log_{16}(x)=7 is x=16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x)+log_{4}(x)+log_{16}(x)=7

lo g_{2} (x) + lo g_{4} (x) + lo g_{16} (x) = 7

x = 16

Solution steps

lo g_{2} (x) + lo g_{4} (x) + lo g_{16} (x) = 7

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

lo g_{x} (3 x) = 2

lo g_{6} (2 x - 5) + 4 = 18

lo g_{7} (x - 9) = 2

lo g_{3} (5 + x) = 4

lo g_{2} (x^{2}) + 4 = 10

What is the answer to log_{2}(x)+log_{4}(x)+log_{16}(x)=7 ?
The answer to log_{2}(x)+log_{4}(x)+log_{16}(x)=7 is x=16
Solve for x: log_{2}(x)+log_{4}(x)+log_{16}(x)=7
The solution is x=16