What is the answer to log_{10}(x^2+4x+17)=2 ?

The answer to log_{10}(x^2+4x+17)=2 is x=-2+sqrt(87),x=-2-sqrt(87)

Solve for x: log_{10}(x^2+4x+17)=2

The solution is x=-2+sqrt(87),x=-2-sqrt(87)

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lo g_{10} (x^{2} + 4 x + 17) = 2

x = - 2 + 87, x = - 2 - 87

Decimal

x = 7.32737 \dots, x = - 11.32737 \dots

Solution steps

lo g_{10} (x^{2} + 4 x + 17) = 2

Apply log rules

x^{2} + 4 x + 17 = 100

Solve

x^{2} + 4 x + 17 = 100 : x = - 2 + 87, x = - 2 - 87

x = - 2 + 87, x = - 2 - 87

9 lo g_{4} (10 x + 4) = 27

lo g_{5} (- 8 x - 3) = 1

lo g_{10} (x^{2}) = 6

lo g_{10} (x) + lo g_{10} (2) = 3

ln (3 x + 2) = 4

What is the answer to log_{10}(x^2+4x+17)=2 ?
The answer to log_{10}(x^2+4x+17)=2 is x=-2+sqrt(87),x=-2-sqrt(87)
Solve for x: log_{10}(x^2+4x+17)=2
The solution is x=-2+sqrt(87),x=-2-sqrt(87)