What is the answer to log_{6}(2x^2-8x+12)=2 ?

The answer to log_{6}(2x^2-8x+12)=2 is x=6,x=-2

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log_{6}(2x^2-8x+12)=2

lo g_{6} (2 x^{2} - 8 x + 12) = 2

x = 6, x = - 2

Solution steps

lo g_{6} (2 x^{2} - 8 x + 12) = 2

Apply log rules

2 x^{2} - 8 x + 12 = 36

Solve

2 x^{2} - 8 x + 12 = 36 : x = 6, x = - 2

x = 6, x = - 2

lo g_{x} (1) = 7

lo g_{3} (x - 1) = e

(ln (x))^{3} = 3 ln (x)

lo g_{4} (x^{2} - x - 5) = 2

lo g_{10} (\frac{x}{0.145}) = - 0.34472

What is the answer to log_{6}(2x^2-8x+12)=2 ?
The answer to log_{6}(2x^2-8x+12)=2 is x=6,x=-2
Solve for x: log_{6}(2x^2-8x+12)=2
The solution is x=6,x=-2