What is the answer to log_{4}(x^2-x-5)=2 ?

The answer to log_{4}(x^2-x-5)=2 is x=(1+sqrt(85))/2 ,x=(1-sqrt(85))/2

Solve for x: log_{4}(x^2-x-5)=2

The solution is x=(1+sqrt(85))/2 ,x=(1-sqrt(85))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{4} (x^{2} - x - 5) = 2

x = \frac{1 + 85}{2}, x = \frac{1 - 85}{2}

Decimal

x = 5.10977 \dots, x = - 4.10977 \dots

Solution steps

lo g_{4} (x^{2} - x - 5) = 2

Apply log rules

x^{2} - x - 5 = 16

Solve

x^{2} - x - 5 = 16 : x = \frac{1 + 85}{2}, x = \frac{1 - 85}{2}

x = \frac{1 + 85}{2}, x = \frac{1 - 85}{2}

lo g_{10} (\frac{x}{0.145}) = - 0.34472

y, x = ln (y - 1) + 2

lo g_{10} (x) + lo g_{10} (x + 3) = 6

lo g_{10} (x) + lo g_{10} (x + 3) = 5

lo g_{10} (2 x - 1) = 3 x

What is the answer to log_{4}(x^2-x-5)=2 ?
The answer to log_{4}(x^2-x-5)=2 is x=(1+sqrt(85))/2 ,x=(1-sqrt(85))/2
Solve for x: log_{4}(x^2-x-5)=2
The solution is x=(1+sqrt(85))/2 ,x=(1-sqrt(85))/2