What is the answer to log_{10}(2x-1)=3x ?

The answer to log_{10}(2x-1)=3x is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(2x-1)=3x

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (2 x - 1) = 3 x

No Solution for x \in R

Solution steps

lo g_{10} (2 x - 1) = 3 x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (2 x - 1)} = 1 0^{3 x}

Simplify

1 0^{l o g_{10} (2 x - 1)} : 2 x - 1

Simplify

1 0^{3 x} : 100 0^{x}

2 x - 1 = 100 0^{x}

Solve

2 x - 1 = 100 0^{x} :

No Solution for

x \in R

No Solution for x \in R

lo g_{6} (4 x - 5) = 1

lo g_{x + 5} (2 x^{2} + 5 x + 1) = 2

lo g_{9} (x) + lo g_{9} (12) = \frac{1}{2} lo g_{9} (100)

5 lo g_{3} (x + 1) + 6 = 7

lo g_{x} (4) = \frac{- 2}{5}

What is the answer to log_{10}(2x-1)=3x ?
The answer to log_{10}(2x-1)=3x is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(2x-1)=3x
The solution is No Solution for x\in\mathbb{R}