What is the answer to log_{9}(x)+log_{9}(12)= 1/2 log_{9}(100) ?

The answer to log_{9}(x)+log_{9}(12)= 1/2 log_{9}(100) is x= 5/6

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log_{9}(x)+log_{9}(12)= 1/2 log_{9}(100)

lo g_{9} (x) + lo g_{9} (12) = \frac{1}{2} lo g_{9} (100)

x = \frac{5}{6}

Decimal

x = 0.83333 \dots

Solution steps

lo g_{9} (x) + lo g_{9} (12) = \frac{1}{2} lo g_{9} (100)

Move

lo g_{9} (12)

to the right side

lo g_{9} (x) = \frac{1}{2} lo g_{9} (100) - lo g_{9} (12)

Apply log rules

x = \frac{5}{6}

Verify Solutions:

x = \frac{5}{6}

True

The solution is

x = \frac{5}{6}

5 lo g_{3} (x + 1) + 6 = 7

lo g_{x} (4) = \frac{- 2}{5}

2 lo g_{10} (7 x) + 1 = 4

20 lo g_{10} (x) = - 6.628

lo g_{6} (x^{2} - x) = 1

What is the answer to log_{9}(x)+log_{9}(12)= 1/2 log_{9}(100) ?
The answer to log_{9}(x)+log_{9}(12)= 1/2 log_{9}(100) is x= 5/6
Solve for x: log_{9}(x)+log_{9}(12)= 1/2 log_{9}(100)
The solution is x= 5/6