What is the answer to log_{9}(x)=-2.5 ?

The answer to log_{9}(x)=-2.5 is x= 1/(9^{2.5)}

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log_{9}(x)=-2.5

lo g_{9} (x) = - 2.5

x = \frac{1}{9 ^{2.5}}

Decimal

x = 0.00411 \dots

Solution steps

lo g_{9} (x) = - 2.5

Apply log rules

x = \frac{1}{9 ^{2.5}}

ln (x) + ln (x + 12) = 4

2 = lo g_{4} (x)

2.1 = ln (6 x)

lo g_{10} (3 x) = lo g_{10} (7) + lo g_{10} (9)

2 x + (\frac{( ln ( x - 2 ) )}{2}) - 6 = 0

What is the answer to log_{9}(x)=-2.5 ?
The answer to log_{9}(x)=-2.5 is x= 1/(9^{2.5)}
Solve for x: log_{9}(x)=-2.5
The solution is x= 1/(9^{2.5)}