What is the answer to log_{10}(3x)=log_{10}(7)+log_{10}(9) ?

The answer to log_{10}(3x)=log_{10}(7)+log_{10}(9) is x=21

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log_{10}(3x)=log_{10}(7)+log_{10}(9)

lo g_{10} (3 x) = lo g_{10} (7) + lo g_{10} (9)

x = 21

Solution steps

lo g_{10} (3 x) = lo g_{10} (7) + lo g_{10} (9)

Apply log rules

3 x = 63

Solve

3 x = 63 : x = 21

x = 21

Verify Solutions:

x = 21

True

The solution is

x = 21

2 x + (\frac{( ln ( x - 2 ) )}{2}) - 6 = 0

lo g_{e} (n) = ln (n)

lo g_{2} (x^{2}) - 4 = 0

lo g_{2} (x + 10) = 8

lo g_{10} (5 x) + lo g_{10} (3 x) = 1

What is the answer to log_{10}(3x)=log_{10}(7)+log_{10}(9) ?
The answer to log_{10}(3x)=log_{10}(7)+log_{10}(9) is x=21
Solve for x: log_{10}(3x)=log_{10}(7)+log_{10}(9)
The solution is x=21