What is the answer to log_{2}(x)+log_{2}(2x)=log_{3}(9) ?

The answer to log_{2}(x)+log_{2}(2x)=log_{3}(9) is x=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x)+log_{2}(2x)=log_{3}(9)

lo g_{2} (x) + lo g_{2} (2 x) = lo g_{3} (9)

x = 2

Decimal

x = 1.41421 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (2 x) = lo g_{3} (9)

Apply log rules

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

ln (x) + ln (x + 8) = 3

lo g_{10} (N + M)

lo g_{10} (7) = \frac{3}{4} lo g_{10} (49) - lo g_{10} (x)

lo g_{x} (\frac{1}{1296}) = 4

lo g_{x} (729) = \frac{3}{2}

What is the answer to log_{2}(x)+log_{2}(2x)=log_{3}(9) ?
The answer to log_{2}(x)+log_{2}(2x)=log_{3}(9) is x=sqrt(2)
Solve for x: log_{2}(x)+log_{2}(2x)=log_{3}(9)
The solution is x=sqrt(2)