What is the answer to log_{x}(2x^2+x-2)=3 ?

The answer to log_{x}(2x^2+x-2)=3 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{x}(2x^2+x-2)=3

lo g_{x} (2 x^{2} + x - 2) = 3

x = 2

Solution steps

lo g_{x} (2 x^{2} + x - 2) = 3

Apply log rules

\frac{ln ( 2 x ^{2} + x - 2 )}{ln ( x )} = 3

Multiply both sides by

ln (x)

\frac{ln ( 2 x ^{2} + x - 2 )}{ln ( x )} ln (x) = 3 ln (x)

Simplify

ln (2 x^{2} + x - 2) = 3 ln (x)

Apply log rules

2 x^{2} + x - 2 = x^{3}

Solve

2 x^{2} + x - 2 = x^{3} : x = 2, x = - 1, x = 1

x = 2, x = - 1, x = 1

Verify Solutions:

x = 2

True

, x = - 1

False

, x = 1

False

The solution is

x = 2

ln (x + 2) = - 5

- 1 = 2 lo g_{\frac{1}{4}} (x)

lo g_{2} (4 x - 3) = 2

lo g_{3} (x^{9}) = 5

lo g_{x} (\frac{1}{5}) = - 1

What is the answer to log_{x}(2x^2+x-2)=3 ?
The answer to log_{x}(2x^2+x-2)=3 is x=2
Solve for x: log_{x}(2x^2+x-2)=3
The solution is x=2