What is the answer to log_{2}(4x-3)=2 ?

The answer to log_{2}(4x-3)=2 is x= 7/4

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log_{2}(4x-3)=2

lo g_{2} (4 x - 3) = 2

x = \frac{7}{4}

Decimal

x = 1.75

Solution steps

lo g_{2} (4 x - 3) = 2

Apply log rules

4 x - 3 = 4

Solve

4 x - 3 = 4 : x = \frac{7}{4}

x = \frac{7}{4}

lo g_{3} (x^{9}) = 5

lo g_{x} (\frac{1}{5}) = - 1

lo g_{2} (x^{2} + 3 x - 3) = 0

lo g_{4} (x + 1) = 1

x, ln (u) = - ln (x)