What is the answer to 3log_{2}(x^2+6x)+5=17 ?

The answer to 3log_{2}(x^2+6x)+5=17 is x=2,x=-8

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3log_{2}(x^2+6x)+5=17

3 lo g_{2} (x^{2} + 6 x) + 5 = 17

x = 2, x = - 8

Solution steps

3 lo g_{2} (x^{2} + 6 x) + 5 = 17

Move

5

to the right side

3 lo g_{2} (x^{2} + 6 x) = 12

Divide both sides by

3

lo g_{2} (x^{2} + 6 x) = 4

Apply log rules

x^{2} + 6 x = 16

Solve

x^{2} + 6 x = 16 : x = 2, x = - 8

x = 2, x = - 8

Verify Solutions:

x = 2

True

, x = - 8

True

The solutions are

x = 2, x = - 8

lo g_{2} (x^{2} - 7 x) = 3

ln (2 x) = 2 + ln (x - 1)

lo g_{7} (x - 5) + 5 = 7

12 x ln (x) + 6 x = 0

6 + lo g_{8} (- 2 x) = 5

What is the answer to 3log_{2}(x^2+6x)+5=17 ?
The answer to 3log_{2}(x^2+6x)+5=17 is x=2,x=-8
Solve for x: 3log_{2}(x^2+6x)+5=17
The solution is x=2,x=-8