What is the answer to log_{10}(x)+log_{10}(x+4)=9 ?

The answer to log_{10}(x)+log_{10}(x+4)=9 is x=(-4+sqrt(4000000016))/2

Solve for x: log_{10}(x)+log_{10}(x+4)=9

The solution is x=(-4+sqrt(4000000016))/2

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lo g_{10} (x) + lo g_{10} (x + 4) = 9

x = \frac{- 4 + 4000000016}{2}

Decimal

x = 31620.77666 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 4) = 9

Apply log rules

x (x + 4) = 1000000000

Solve

x (x + 4) = 1000000000 : x = \frac{- 4 + 4000000016}{2}, x = \frac{- 4 - 4000000016}{2}

x = \frac{- 4 + 4000000016}{2}, x = \frac{- 4 - 4000000016}{2}

Verify Solutions:

x = \frac{- 4 + 4000000016}{2}

True

, x = \frac{- 4 - 4000000016}{2}

False

The solution is

x = \frac{- 4 + 4000000016}{2}

4.314 = - lo g_{10} (x)

0 = ln (y + 2)

lo g_{2} (7 x + 3) = 1

lo g_{5} (x - 2) = 2

lo g_{3} (8 - x) = 3

What is the answer to log_{10}(x)+log_{10}(x+4)=9 ?
The answer to log_{10}(x)+log_{10}(x+4)=9 is x=(-4+sqrt(4000000016))/2
Solve for x: log_{10}(x)+log_{10}(x+4)=9
The solution is x=(-4+sqrt(4000000016))/2