What is the answer to 2*log_{10}(3-x)=-1 ?

The answer to 2*log_{10}(3-x)=-1 is x=(-1+3sqrt(10))/(sqrt(10))

Solve for x: 2*log_{10}(3-x)=-1

The solution is x=(-1+3sqrt(10))/(sqrt(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 \cdot lo g_{10} (3 - x) = - 1

x = \frac{- 1 + 3 10}{10}

Decimal

x = 2.68377 \dots

Solution steps

2 lo g_{10} (3 - x) = - 1

Divide both sides by

2

lo g_{10} (3 - x) = - \frac{1}{2}

Apply log rules

3 - x = \frac{1}{10}

Solve

3 - x = \frac{1}{10} : x = \frac{- 1 + 3 10}{10}

x = \frac{- 1 + 3 10}{10}

Verify Solutions:

x = \frac{- 1 + 3 10}{10}

True

The solution is

x = \frac{- 1 + 3 10}{10}

lo g_{2} (8 + x) = 3

14.47 = \frac{x - 11}{ln ( \frac{x}{11} )}

f, f^{- 1} (x) = ln (x)

lo g_{\frac{1}{2}} (1 - 3 x) = 2

- 20 = 10 \times lo g_{10} (x)

What is the answer to 2*log_{10}(3-x)=-1 ?
The answer to 2*log_{10}(3-x)=-1 is x=(-1+3sqrt(10))/(sqrt(10))
Solve for x: 2*log_{10}(3-x)=-1
The solution is x=(-1+3sqrt(10))/(sqrt(10))