What is the answer to -|b+6|=|3b-2| ?

The answer to -|b+6|=|3b-2| is No Solution for b\in\mathbb{R}

Solve for b: -|b+6|=|3b-2|

The solution is No Solution for b\in\mathbb{R}

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- ∣ b + 6 ∣ = ∣ 3 b - 2 ∣

No Solution for b \in R

Solution steps

- ∣ b + 6 ∣ = ∣ 3 b - 2 ∣

Find positive and negative intervals

b < - 6, - 6 \leq b < \frac{2}{3}, b \geq \frac{2}{3}

Solve the inequality for each interval

No Solution for b \in R

x^{2} - 2 ∣ x ∣ - 1 = 0

∣ x - 3 ∣ = ∣ x + 3 ∣

∣ x + 1 ∣ = (x - 41)^{2}

10 - ∣ 3 x + 2 ∣ = 7

∣ 2 x + 5 ∣ = 5

What is the answer to -|b+6|=|3b-2| ?
The answer to -|b+6|=|3b-2| is No Solution for b\in\mathbb{R}
Solve for b: -|b+6|=|3b-2|
The solution is No Solution for b\in\mathbb{R}