What are the solutions to the equation x(x-2)=48 ?

The solutions to the equation x(x-2)=48 are x=8,x=-6

Find the zeros of x(x-2)=48

The zeros of x(x-2)=48 are x=8,x=-6

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x (x - 2) = 48

x = 8, x = - 6

Solution steps

x (x - 2) = 48

Expand

x (x - 2) : x^{2} - 2 x

x^{2} - 2 x = 48

Move

48

to the left side

x^{2} - 2 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 48) = 14

x_{1, 2} = \frac{- ( - 2 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 14}{2 \cdot 1}

x = \frac{- ( - 2 ) + 14}{2 \cdot 1} : 8

x = \frac{- ( - 2 ) - 14}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 8, x = - 6

x^{2} + 1 x + 9 = 0

50 m = 30 + 0.18 m

4 a^{2} b^{2} + 16 ab + 12 a

\frac{( 3 x - 6 ) ^{2}}{( 2 - x ) ^{2}}

3 x + 9 + 4 x + x = 0 x + 0

What are the solutions to the equation x(x-2)=48 ?
The solutions to the equation x(x-2)=48 are x=8,x=-6
Find the zeros of x(x-2)=48
The zeros of x(x-2)=48 are x=8,x=-6