What are the solutions to the equation 3w^2-12w=0 ?

The solutions to the equation 3w^2-12w=0 are w=4,w=0

Find the zeros of 3w^2-12w=0

The zeros of 3w^2-12w=0 are w=4,w=0

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3 w^{2} - 12 w = 0

w = 4, w = 0

Solution steps

3 w^{2} - 12 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 0 = 12

w_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 3}, w_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 3}

w = \frac{- ( - 12 ) + 12}{2 \cdot 3} : 4

w = \frac{- ( - 12 ) - 12}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

w = 4, w = 0

y (3 x + 1) - 3 x - 1

- 13 < x + 9

x^{2} + 18 x + 78 = 0

(\frac{- 8}{2})^{2}

e^{- \frac{1}{x}}

What are the solutions to the equation 3w^2-12w=0 ?
The solutions to the equation 3w^2-12w=0 are w=4,w=0
Find the zeros of 3w^2-12w=0
The zeros of 3w^2-12w=0 are w=4,w=0