What are the solutions to the equation solvefor x,2x^2-5x=3 ?

The solutions to the equation solvefor x,2x^2-5x=3 are x=3,x=-1/2

Find the zeros of solvefor x,2x^2-5x=3

The zeros of solvefor x,2x^2-5x=3 are x=3,x=-1/2

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x, 2 x^{2} - 5 x = 3

x = 3, x = - \frac{1}{2}

Solution steps

2 x^{2} - 5 x = 3

Move

3

to the left side

2 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

x = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

x = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

- 16 - 10

15%

3.4%

x^{3} - 7 = 0, a = 2

5 w^{2} - 3 = 0

What are the solutions to the equation solvefor x,2x^2-5x=3 ?
The solutions to the equation solvefor x,2x^2-5x=3 are x=3,x=-1/2
Find the zeros of solvefor x,2x^2-5x=3
The zeros of solvefor x,2x^2-5x=3 are x=3,x=-1/2